28+8x=8x(x+3)+2

Solution for 28+8x=8x(x+3)+2 equation:

28+8x=8x(x+3)+2

We move all terms to the left:

28+8x-(8x(x+3)+2)=0


We calculate terms in parentheses: -(8x(x+3)+2), so:

8x(x+3)+2

We multiply parentheses

8x^2+24x+2

Back to the equation:

-(8x^2+24x+2)


We get rid of parentheses

-8x^2+8x-24x-2+28=0

We add all the numbers together, and all the variables

-8x^2-16x+26=0

a = -8; b = -16; c = +26;
Δ = b2-4ac
Δ = -162-4·(-8)·26
Δ = 1088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1088}=\sqrt{64*17}=\sqrt{64}*\sqrt{17}=8\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{17}}{2*-8}=\frac{16-8\sqrt{17}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{17}}{2*-8}=\frac{16+8\sqrt{17}}{-16}
$