28+4r=-8(1-r)+8r

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Solution for 28+4r=-8(1-r)+8r equation: 



28+4r=-8(1-r)+8r

We move all terms to the left:

28+4r-(-8(1-r)+8r)=0

We add all the numbers together, and all the variables

4r-(-8(-1r+1)+8r)+28=0



We calculate terms in parentheses: -(-8(-1r+1)+8r), so:

-8(-1r+1)+8r

We add all the numbers together, and all the variables

8r-8(-1r+1)

We multiply parentheses

8r+8r-8

We add all the numbers together, and all the variables

16r-8

Back to the equation:

-(16r-8)



We get rid of parentheses

4r-16r+8+28=0

We add all the numbers together, and all the variables

-12r+36=0

We move all terms containing r to the left, all other terms to the right

-12r=-36

r=-36/-12

r=+3

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