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28+2(x-5)=6(x+3)-5x
We move all terms to the left:
28+2(x-5)-(6(x+3)-5x)=0
We multiply parentheses
2x-(6(x+3)-5x)-10+28=0
We calculate terms in parentheses: -(6(x+3)-5x), so:We add all the numbers together, and all the variables
6(x+3)-5x
We add all the numbers together, and all the variables
-5x+6(x+3)
We multiply parentheses
-5x+6x+18
We add all the numbers together, and all the variables
x+18
Back to the equation:
-(x+18)
2x-(x+18)+18=0
We get rid of parentheses
2x-x-18+18=0
We add all the numbers together, and all the variables
x=0
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