28(2x-1)=7(x+3+2x)

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Solution for 28(2x-1)=7(x+3+2x) equation: 



28(2x-1)=7(x+3+2x)

We move all terms to the left:

28(2x-1)-(7(x+3+2x))=0

We add all the numbers together, and all the variables

28(2x-1)-(7(3x+3))=0

We multiply parentheses

56x-(7(3x+3))-28=0



We calculate terms in parentheses: -(7(3x+3)), so:

7(3x+3)

We multiply parentheses

21x+21

Back to the equation:

-(21x+21)



We get rid of parentheses

56x-21x-21-28=0

We add all the numbers together, and all the variables

35x-49=0

We move all terms containing x to the left, all other terms to the right

35x=49

x=49/35

x=1+2/5

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