28(2c+4)=2(c+7)+c

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Solution for 28(2c+4)=2(c+7)+c equation: 



28(2c+4)=2(c+7)+c

We move all terms to the left:

28(2c+4)-(2(c+7)+c)=0

We multiply parentheses

56c-(2(c+7)+c)+112=0



We calculate terms in parentheses: -(2(c+7)+c), so:

2(c+7)+c

We add all the numbers together, and all the variables

c+2(c+7)

We multiply parentheses

c+2c+14

We add all the numbers together, and all the variables

3c+14

Back to the equation:

-(3c+14)



We get rid of parentheses

56c-3c-14+112=0

We add all the numbers together, and all the variables

53c+98=0

We move all terms containing c to the left, all other terms to the right

53c=-98

c=-98/53

c=-1+45/53

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