28(20-12x)=56

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Solution for 28(20-12x)=56 equation: 



28(20-12x)=56

We move all terms to the left:

28(20-12x)-(56)=0

We add all the numbers together, and all the variables

28(-12x+20)-56=0

We multiply parentheses

-336x+560-56=0

We add all the numbers together, and all the variables

-336x+504=0

We move all terms containing x to the left, all other terms to the right

-336x=-504

x=-504/-336

x=1+1/2

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