If it's not what You are looking for type in the equation solver your own equation and let us solve it.
27x^2-3=0
a = 27; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·27·(-3)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18}{2*27}=\frac{-18}{54} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18}{2*27}=\frac{18}{54} =1/3 $
| -6b+12=2b-44 | | 4(5b-)=268 | | -6b=12=2b-44 | | n=1/8;/n | | 5n-13=3n+21 | | 1.66666667=-(x-5) | | 13y−6=5y+10 | | 6x=3,106x | | 9t+153=14t | | 9^2m=27 | | 12/x =4/9 | | 12/x=4/9 | | (3/8)s=9 | | (2/3)n=(7/8) | | 3x+32=11x | | 3x-4=6x-64 | | 3x-4=6x-64= | | 3x-4+6x-64=180 | | 3x-4+6x-64=90 | | -5d+3=11 | | 3.5p=1.5 | | t÷4/9=4 | | 11x-32=8x+20 | | 5(6^3x)=11 | | -5+12=5x-12 | | x²-3x-70=0 | | 127=9x+19 | | 128=7x+16 | | (8x-22)=6x | | 6a+7=15a–38 | | 180-2x=90 | | 7n2-42=-35n |