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27p-9p^2=0
a = -9; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·(-9)·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*-9}=\frac{-54}{-18} =+3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*-9}=\frac{0}{-18} =0 $
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