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27m^2=(9m)
We move all terms to the left:
27m^2-((9m))=0
determiningTheFunctionDomain 27m^2-9m=0
a = 27; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·27·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*27}=\frac{0}{54} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*27}=\frac{18}{54} =1/3 $
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