27m2=3

Solution for 27m2=3 equation:

27m^2=3

We move all terms to the left:

27m^2-(3)=0

a = 27; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·27·(-3)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18}{2*27}=\frac{-18}{54}
=-1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18}{2*27}=\frac{18}{54}
=1/3
$