27=7(u-3)+5u

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Solution for 27=7(u-3)+5u equation:



27=7(u-3)+5u
We move all terms to the left:
27-(7(u-3)+5u)=0
We calculate terms in parentheses: -(7(u-3)+5u), so:
7(u-3)+5u
We add all the numbers together, and all the variables
5u+7(u-3)
We multiply parentheses
5u+7u-21
We add all the numbers together, and all the variables
12u-21
Back to the equation:
-(12u-21)
We get rid of parentheses
-12u+21+27=0
We add all the numbers together, and all the variables
-12u+48=0
We move all terms containing u to the left, all other terms to the right
-12u=-48
u=-48/-12
u=+4

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