27=3(4+a)

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Solution for 27=3(4+a) equation: 



27=3(4+a)

We move all terms to the left:

27-(3(4+a))=0

We add all the numbers together, and all the variables

-(3(a+4))+27=0



We calculate terms in parentheses: -(3(a+4)), so:

3(a+4)

We multiply parentheses

3a+12

Back to the equation:

-(3a+12)



We get rid of parentheses

-3a-12+27=0

We add all the numbers together, and all the variables

-3a+15=0

We move all terms containing a to the left, all other terms to the right

-3a=-15

a=-15/-3

a=+5

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