27=3(3n-3)-3(2n-5)

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Solution for 27=3(3n-3)-3(2n-5) equation: 



27=3(3n-3)-3(2n-5)

We move all terms to the left:

27-(3(3n-3)-3(2n-5))=0



We calculate terms in parentheses: -(3(3n-3)-3(2n-5)), so:

3(3n-3)-3(2n-5)

We multiply parentheses

9n-6n-9+15

We add all the numbers together, and all the variables

3n+6

Back to the equation:

-(3n+6)



We get rid of parentheses

-3n-6+27=0

We add all the numbers together, and all the variables

-3n+21=0

We move all terms containing n to the left, all other terms to the right

-3n=-21

n=-21/-3

n=+7

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