27=2(y-4)-7y

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Solution for 27=2(y-4)-7y equation: 



27=2(y-4)-7y

We move all terms to the left:

27-(2(y-4)-7y)=0



We calculate terms in parentheses: -(2(y-4)-7y), so:

2(y-4)-7y

We add all the numbers together, and all the variables

-7y+2(y-4)

We multiply parentheses

-7y+2y-8

We add all the numbers together, and all the variables

-5y-8

Back to the equation:

-(-5y-8)



We get rid of parentheses

5y+8+27=0

We add all the numbers together, and all the variables

5y+35=0

We move all terms containing y to the left, all other terms to the right

5y=-35

y=-35/5

y=-7

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