27=1/3(6x-9)+3x

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Solution for 27=1/3(6x-9)+3x equation: 



27=1/3(6x-9)+3x

We move all terms to the left:

27-(1/3(6x-9)+3x)=0



Domain of the equation: 3(6x-9)+3x)!=0

x∈R



We multiply all the terms by the denominator


-(1+27*3(6x-9)+3x)=0



We calculate terms in parentheses: -(1+27*3(6x-9)+3x), so:

1+27*3(6x-9)+3x

determiningTheFunctionDomain
27*3(6x-9)+3x+1

We add all the numbers together, and all the variables

3x+27*3(6x-9)+1

Wy multiply elements

3x+81x(6+1

Back to the equation:

-(3x+81x(6+1)



We add all the numbers together, and all the variables

-(3x+81x7=0

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