279=(n-1)+(n)+(n+1)

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Solution for 279=(n-1)+(n)+(n+1) equation: 



279=(n-1)+(n)+(n+1)

We move all terms to the left:

279-((n-1)+(n)+(n+1))=0



We calculate terms in parentheses: -((n-1)+n+(n+1)), so:

(n-1)+n+(n+1)

We add all the numbers together, and all the variables

n+(n-1)+(n+1)

We get rid of parentheses

n+n+n-1+1

We add all the numbers together, and all the variables

3n

Back to the equation:

-(3n)



We move all terms containing n to the left, all other terms to the right

-3n=-279

n=-279/-3

n=+93

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