27+3a=6a-5(1+7a)

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Solution for 27+3a=6a-5(1+7a) equation: 



27+3a=6a-5(1+7a)

We move all terms to the left:

27+3a-(6a-5(1+7a))=0

We add all the numbers together, and all the variables

3a-(6a-5(7a+1))+27=0



We calculate terms in parentheses: -(6a-5(7a+1)), so:

6a-5(7a+1)

We multiply parentheses

6a-35a-5

We add all the numbers together, and all the variables

-29a-5

Back to the equation:

-(-29a-5)



We get rid of parentheses

3a+29a+5+27=0

We add all the numbers together, and all the variables

32a+32=0

We move all terms containing a to the left, all other terms to the right

32a=-32

a=-32/32

a=-1

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