27(v-3)(3v-4)/9(3v-4)(v+2)

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Solution for 27(v-3)(3v-4)/9(3v-4)(v+2) equation: 


v in (-oo:+oo)

((27*(v-3)*(3*v-4))/9)*(3*v-4)*(v+2) = 0

(27*(v-3)*(3*v-4)^2*(v+2))/9 = 0

( 3*v-4 )

3*v-4 = 0 // + 4

3*v = 4 // : 3

v = 4/3

( v+2 )

v+2 = 0 // - 2

v = -2

( v-3 )

v-3 = 0 // + 3

v = 3

v in { 4/3, 4/3, -2, 3 }

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