26=5/9(x-32)

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Solution for 26=5/9(x-32) equation:



26=5/9(x-32)
We move all terms to the left:
26-(5/9(x-32))=0
Domain of the equation: 9(x-32))!=0
x∈R
We multiply all the terms by the denominator
-(5+26*9(x-32))=0
We calculate terms in parentheses: -(5+26*9(x-32)), so:
5+26*9(x-32)
determiningTheFunctionDomain 26*9(x-32)+5
Wy multiply elements
234x(x+5
Back to the equation:
-(234x(x+5)
We calculate terms in parentheses: -(234x(x+5), so:
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We calculate terms in parentheses: -(234x(x+5), so:
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We calculate terms in parentheses: -(234x(x+5), so:
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We calculate terms in parentheses: -(234x(x+5), so:
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We calculate terms in parentheses: -(234x(x+5), so:
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We calculate terms in parentheses: -(234x(x+5), so:
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We calculate terms in parentheses: -(234x(x+5), so:
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We calculate terms in parentheses: -(234x(x+5), so:
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We calculate terms in parentheses: -(234x(x+5), so:
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We calculate terms in parentheses: -(234x(x+5), so:
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We calculate terms in parentheses: -(234x(x+5), so:
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We calculate terms in parentheses: -(234x(x+5), so:
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We calculate terms in parentheses: -(234x(x+5), so:
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We calculate terms in parentheses: -(234x(x+5), so:
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