26=2(2x-2)+2(10-x)

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Solution for 26=2(2x-2)+2(10-x) equation: 



26=2(2x-2)+2(10-x)

We move all terms to the left:

26-(2(2x-2)+2(10-x))=0

We add all the numbers together, and all the variables

-(2(2x-2)+2(-1x+10))+26=0



We calculate terms in parentheses: -(2(2x-2)+2(-1x+10)), so:

2(2x-2)+2(-1x+10)

We multiply parentheses

4x-2x-4+20

We add all the numbers together, and all the variables

2x+16

Back to the equation:

-(2x+16)



We get rid of parentheses

-2x-16+26=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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