26=14-(2z-5)

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Solution for 26=14-(2z-5) equation: 



26=14-(2z-5)

We move all terms to the left:

26-(14-(2z-5))=0



We calculate terms in parentheses: -(14-(2z-5)), so:

14-(2z-5)

determiningTheFunctionDomain
-(2z-5)+14

We get rid of parentheses

-2z+5+14

We add all the numbers together, and all the variables

-2z+19

Back to the equation:

-(-2z+19)



We get rid of parentheses

2z-19+26=0

We add all the numbers together, and all the variables

2z+7=0

We move all terms containing z to the left, all other terms to the right

2z=-7

z=-7/2

z=-3+1/2

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