260(0.135)/298=140(0.79)/t2

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Solution for 260(0.135)/298=140(0.79)/t2 equation:


D( t )

t^2 = 0

t^2 = 0

t^2 = 0

1*t^2 = 0 // : 1

t^2 = 0

t = 0

t in (-oo:0) U (0:+oo)

(0.135*260)/298 = (0.79*140)/(t^2) // - (0.79*140)/(t^2)

(0.135*260)/298-((0.79*140)/(t^2)) = 0

(0.135*260)/298-110.6*t^-2 = 0

-110.6*t^-2 = -0.11778523 // : -110.6

t^-2 = 0.00106497

-2 < 0

1/(t^2) = 0.00106497 // * t^2

1 = 0.00106497*t^2 // : 0.00106497

938.99358667 = t^2

t^2 = 938.99358667 // ^ 1/2

abs(t) = 938.99358667^(1/2)

t = 938.99358667^(1/2) or t = -938.99358667^(1/2)

t in { 938.99358667^(1/2), -938.99358667^(1/2) }

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