260^2+288^2=c^2

Solution for 260^2+288^2=c^2 equation:

260^2+288^2=c^2

We move all terms to the left:

260^2+288^2-(c^2)=0

We add all the numbers together, and all the variables

-1c^2+150544=0

a = -1; b = 0; c = +150544;
Δ = b2-4ac
Δ = 02-4·(-1)·150544
Δ = 602176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{602176}=776$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-776}{2*-1}=\frac{-776}{-2}
=+388
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+776}{2*-1}=\frac{776}{-2}
=-388
$