26-2(2x+2)=4(x+2)+62

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Solution for 26-2(2x+2)=4(x+2)+62 equation: 



26-2(2x+2)=4(x+2)+62

We move all terms to the left:

26-2(2x+2)-(4(x+2)+62)=0

We multiply parentheses

-4x-(4(x+2)+62)-4+26=0



We calculate terms in parentheses: -(4(x+2)+62), so:

4(x+2)+62

We multiply parentheses

4x+8+62

We add all the numbers together, and all the variables

4x+70

Back to the equation:

-(4x+70)



We add all the numbers together, and all the variables

-4x-(4x+70)+22=0

We get rid of parentheses

-4x-4x-70+22=0

We add all the numbers together, and all the variables

-8x-48=0

We move all terms containing x to the left, all other terms to the right

-8x=48

x=48/-8

x=-6

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