26-(2c+3)=2(c+4)+2

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Solution for 26-(2c+3)=2(c+4)+2 equation: 



26-(2c+3)=2(c+4)+2

We move all terms to the left:

26-(2c+3)-(2(c+4)+2)=0

We get rid of parentheses

-2c-(2(c+4)+2)-3+26=0



We calculate terms in parentheses: -(2(c+4)+2), so:

2(c+4)+2

We multiply parentheses

2c+8+2

We add all the numbers together, and all the variables

2c+10

Back to the equation:

-(2c+10)



We add all the numbers together, and all the variables

-2c-(2c+10)+23=0

We get rid of parentheses

-2c-2c-10+23=0

We add all the numbers together, and all the variables

-4c+13=0

We move all terms containing c to the left, all other terms to the right

-4c=-13

c=-13/-4

c=3+1/4

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