25z2+60z+36=0

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Solution for 25z2+60z+36=0 equation: 



25z^2+60z+36=0

a = 25; b = 60; c = +36;
Δ = b2-4ac
Δ = 602-4·25·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{-60}{50}=-1+1/5$

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