If it's not what You are looking for type in the equation solver your own equation and let us solve it.
25x^2=65
We move all terms to the left:
25x^2-(65)=0
a = 25; b = 0; c = -65;
Δ = b2-4ac
Δ = 02-4·25·(-65)
Δ = 6500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6500}=\sqrt{100*65}=\sqrt{100}*\sqrt{65}=10\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{65}}{2*25}=\frac{0-10\sqrt{65}}{50} =-\frac{10\sqrt{65}}{50} =-\frac{\sqrt{65}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{65}}{2*25}=\frac{0+10\sqrt{65}}{50} =\frac{10\sqrt{65}}{50} =\frac{\sqrt{65}}{5} $
| -27=7b-13 | | 30=x/3+10 | | 4r-2000=-5r+7000 | | D=o | | 4-5x=2+6x | | 20x-5+10+5x=180 | | s−–79=238 | | a⁵+11a-12)÷(a²-2a+3=) | | (x-40)=0.05x-2 | | 13b=884 | | -20=a-39 | | 6r−9(r+9)=4r+9+3r | | w−49=5 | | w+57=73 | | 4g-129=5 | | 11=p−1 | | 11x+7=26x-2 | | 2a+3B+4C;A=1.2,B=3.5,C= | | 12c+4+3c=38- | | 61x+21=30x+58 | | 28x+2=30x | | 8|m|=128 | | (7x+4)/5=−2 | | 12x+9=17+12x | | S(25)=7-4n | | 12+9=17+12x | | 26=a/6+2 | | 0.05x-2=(x-40) | | 1/3x+1=1/9x-1/3 | | H(-10)=14-x | | -4r+36=2(-7r+8) | | H(2)=14-x |