25x2-256=0

Solution for 25x2-256=0 equation:

25x^2-256=0

a = 25; b = 0; c = -256;
Δ = b2-4ac
Δ = 02-4·25·(-256)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*25}=\frac{-160}{50}
=-3+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*25}=\frac{160}{50}
=3+1/5
$