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25x^2-20x-1221=0
a = 25; b = -20; c = -1221;
Δ = b2-4ac
Δ = -202-4·25·(-1221)
Δ = 122500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{122500}=350$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-350}{2*25}=\frac{-330}{50} =-6+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+350}{2*25}=\frac{370}{50} =7+2/5 $
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