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25x^2-100x-96=0
a = 25; b = -100; c = -96;
Δ = b2-4ac
Δ = -1002-4·25·(-96)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19600}=140$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-140}{2*25}=\frac{-40}{50} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+140}{2*25}=\frac{240}{50} =4+4/5 $
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