25x2+24x-400=0

Solution for 25x2+24x-400=0 equation:

25x^2+24x-400=0

a = 25; b = 24; c = -400;
Δ = b2-4ac
Δ = 242-4·25·(-400)
Δ = 40576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40576}=\sqrt{64*634}=\sqrt{64}*\sqrt{634}=8\sqrt{634}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-8\sqrt{634}}{2*25}=\frac{-24-8\sqrt{634}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+8\sqrt{634}}{2*25}=\frac{-24+8\sqrt{634}}{50}
$