25x2+20+4=75

Solution for 25x2+20+4=75 equation:

25x^2+20+4=75

We move all terms to the left:

25x^2+20+4-(75)=0

We add all the numbers together, and all the variables

25x^2-51=0

a = 25; b = 0; c = -51;
Δ = b2-4ac
Δ = 02-4·25·(-51)
Δ = 5100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5100}=\sqrt{100*51}=\sqrt{100}*\sqrt{51}=10\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{51}}{2*25}=\frac{0-10\sqrt{51}}{50}
=-\frac{10\sqrt{51}}{50}
=-\frac{\sqrt{51}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{51}}{2*25}=\frac{0+10\sqrt{51}}{50}
=\frac{10\sqrt{51}}{50}
=\frac{\sqrt{51}}{5}
$