25x(10x+250)=425

Solution for 25x(10x+250)=425 equation:

25x(10x+250)=425

We move all terms to the left:

25x(10x+250)-(425)=0

We multiply parentheses

250x^2+6250x-425=0

a = 250; b = 6250; c = -425;
Δ = b2-4ac
Δ = 62502-4·250·(-425)
Δ = 39487500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{39487500}=\sqrt{202500*195}=\sqrt{202500}*\sqrt{195}=450\sqrt{195}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6250)-450\sqrt{195}}{2*250}=\frac{-6250-450\sqrt{195}}{500}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6250)+450\sqrt{195}}{2*250}=\frac{-6250+450\sqrt{195}}{500}
$