25=3(y+5)-5y

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Solution for 25=3(y+5)-5y equation: 



25=3(y+5)-5y

We move all terms to the left:

25-(3(y+5)-5y)=0



We calculate terms in parentheses: -(3(y+5)-5y), so:

3(y+5)-5y

We add all the numbers together, and all the variables

-5y+3(y+5)

We multiply parentheses

-5y+3y+15

We add all the numbers together, and all the variables

-2y+15

Back to the equation:

-(-2y+15)



We get rid of parentheses

2y-15+25=0

We add all the numbers together, and all the variables

2y+10=0

We move all terms containing y to the left, all other terms to the right

2y=-10

y=-10/2

y=-5

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