25=16t2+36t+5

Solution for 25=16t2+36t+5 equation:

25=16t^2+36t+5

We move all terms to the left:

25-(16t^2+36t+5)=0

We get rid of parentheses

-16t^2-36t-5+25=0

We add all the numbers together, and all the variables

-16t^2-36t+20=0

a = -16; b = -36; c = +20;
Δ = b2-4ac
Δ = -362-4·(-16)·20
Δ = 2576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2576}=\sqrt{16*161}=\sqrt{16}*\sqrt{161}=4\sqrt{161}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{161}}{2*-16}=\frac{36-4\sqrt{161}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{161}}{2*-16}=\frac{36+4\sqrt{161}}{-32}
$