25=16-3(b-2)

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Solution for 25=16-3(b-2) equation: 



25=16-3(b-2)

We move all terms to the left:

25-(16-3(b-2))=0



We calculate terms in parentheses: -(16-3(b-2)), so:

16-3(b-2)

determiningTheFunctionDomain
-3(b-2)+16

We multiply parentheses

-3b+6+16

We add all the numbers together, and all the variables

-3b+22

Back to the equation:

-(-3b+22)



We get rid of parentheses

3b-22+25=0

We add all the numbers together, and all the variables

3b+3=0

We move all terms containing b to the left, all other terms to the right

3b=-3

b=-3/3

b=-1

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