25=11/12b=27

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Solution for 25=11/12b=27 equation: 



25=11/12b=27

We move all terms to the left:

25-(11/12b)=0



Domain of the equation: 12b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

-(+11/12b)+25=0

We get rid of parentheses

-11/12b+25=0

We multiply all the terms by the denominator


25*12b-11=0

Wy multiply elements

300b-11=0

We move all terms containing b to the left, all other terms to the right

300b=11

b=11/300

b=11/300

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