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252=4-8(5v+4)
We move all terms to the left:
252-(4-8(5v+4))=0
We calculate terms in parentheses: -(4-8(5v+4)), so:We get rid of parentheses
4-8(5v+4)
determiningTheFunctionDomain -8(5v+4)+4
We multiply parentheses
-40v-32+4
We add all the numbers together, and all the variables
-40v-28
Back to the equation:
-(-40v-28)
40v+28+252=0
We add all the numbers together, and all the variables
40v+280=0
We move all terms containing v to the left, all other terms to the right
40v=-280
v=-280/40
v=-7
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