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251/42=1/6b+1-2b
We move all terms to the left:
251/42-(1/6b+1-2b)=0
Domain of the equation: 6b+1-2b)!=0We add all the numbers together, and all the variables
We move all terms containing b to the left, all other terms to the right
6b-2b)!=-1
b∈R
-(-2b+1/6b+1)+251/42=0
We get rid of parentheses
2b-1/6b-1+251/42=0
We calculate fractions
There is no solution for this equation
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