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25/28x=x-9
We move all terms to the left:
25/28x-(x-9)=0
Domain of the equation: 28x!=0We get rid of parentheses
x!=0/28
x!=0
x∈R
25/28x-x+9=0
We multiply all the terms by the denominator
-x*28x+9*28x+25=0
Wy multiply elements
-28x^2+252x+25=0
a = -28; b = 252; c = +25;
Δ = b2-4ac
Δ = 2522-4·(-28)·25
Δ = 66304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{66304}=\sqrt{256*259}=\sqrt{256}*\sqrt{259}=16\sqrt{259}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(252)-16\sqrt{259}}{2*-28}=\frac{-252-16\sqrt{259}}{-56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(252)+16\sqrt{259}}{2*-28}=\frac{-252+16\sqrt{259}}{-56} $
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