25.12=(1/3)(12.56h)

Solution for 25.12=(1/3)(12.56h) equation:

25.12=(1/3)(12.56h)

We move all terms to the left:

25.12-((1/3)(12.56h))=0


Domain of the equation: 3)(12.56h))!=0

h∈R


We add all the numbers together, and all the variables

-((+1/3)(+12.56h))+25.12=0

We multiply parentheses ..

-((+12h^2))+25.12=0


We calculate terms in parentheses: -((+12h^2)), so:

(+12h^2)

We get rid of parentheses

12h^2

Back to the equation:

-(12h^2)


a = -12; b = 0; c = +25.12;
Δ = b2-4ac
Δ = 02-4·(-12)·25.12
Δ = 1205.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1205.76}}{2*-12}=\frac{0-\sqrt{1205.76}}{-24}
=-\frac{\sqrt{}}{-24}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1205.76}}{2*-12}=\frac{0+\sqrt{1205.76}}{-24}
=\frac{\sqrt{}}{-24}
$