25-2z=5(z-2)

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Solution for 25-2z=5(z-2) equation: 



25-2z=5(z-2)

We move all terms to the left:

25-2z-(5(z-2))=0



We calculate terms in parentheses: -(5(z-2)), so:

5(z-2)

We multiply parentheses

5z-10

Back to the equation:

-(5z-10)



We get rid of parentheses

-2z-5z+10+25=0

We add all the numbers together, and all the variables

-7z+35=0

We move all terms containing z to the left, all other terms to the right

-7z=-35

z=-35/-7

z=+5

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