25-1/5b=35

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Solution for 25-1/5b=35 equation: 



25-1/5b=35

We move all terms to the left:

25-1/5b-(35)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We add all the numbers together, and all the variables

-1/5b-10=0

We multiply all the terms by the denominator


-10*5b-1=0

Wy multiply elements

-50b-1=0

We move all terms containing b to the left, all other terms to the right

-50b=1

b=1/-50

b=-1/50

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