25-(m+2)-3(2m+2)=38

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Solution for 25-(m+2)-3(2m+2)=38 equation: 



25-(m+2)-3(2m+2)=38

We move all terms to the left:

25-(m+2)-3(2m+2)-(38)=0

We add all the numbers together, and all the variables

-(m+2)-3(2m+2)-13=0

We multiply parentheses

-(m+2)-6m-6-13=0

We get rid of parentheses

-m-6m-2-6-13=0

We add all the numbers together, and all the variables

-7m-21=0

We move all terms containing m to the left, all other terms to the right

-7m=21

m=21/-7

m=-3

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