25-(3c+4)=2(c+6)+c

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Solution for 25-(3c+4)=2(c+6)+c equation:


Simplifying
25 + -1(3c + 4) = 2(c + 6) + c

Reorder the terms:
25 + -1(4 + 3c) = 2(c + 6) + c
25 + (4 * -1 + 3c * -1) = 2(c + 6) + c
25 + (-4 + -3c) = 2(c + 6) + c

Combine like terms: 25 + -4 = 21
21 + -3c = 2(c + 6) + c

Reorder the terms:
21 + -3c = 2(6 + c) + c
21 + -3c = (6 * 2 + c * 2) + c
21 + -3c = (12 + 2c) + c

Combine like terms: 2c + c = 3c
21 + -3c = 12 + 3c

Solving
21 + -3c = 12 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
21 + -3c + -3c = 12 + 3c + -3c

Combine like terms: -3c + -3c = -6c
21 + -6c = 12 + 3c + -3c

Combine like terms: 3c + -3c = 0
21 + -6c = 12 + 0
21 + -6c = 12

Add '-21' to each side of the equation.
21 + -21 + -6c = 12 + -21

Combine like terms: 21 + -21 = 0
0 + -6c = 12 + -21
-6c = 12 + -21

Combine like terms: 12 + -21 = -9
-6c = -9

Divide each side by '-6'.
c = 1.5

Simplifying
c = 1.5

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