25-(2c+3)=2(c+6)+6

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Solution for 25-(2c+3)=2(c+6)+6 equation: 


Simplifying
25 + -1(2c + 3) = 2(c + 6) + 6

Reorder the terms:
25 + -1(3 + 2c) = 2(c + 6) + 6
25 + (3 * -1 + 2c * -1) = 2(c + 6) + 6
25 + (-3 + -2c) = 2(c + 6) + 6

Combine like terms: 25 + -3 = 22
22 + -2c = 2(c + 6) + 6

Reorder the terms:
22 + -2c = 2(6 + c) + 6
22 + -2c = (6 * 2 + c * 2) + 6
22 + -2c = (12 + 2c) + 6

Reorder the terms:
22 + -2c = 12 + 6 + 2c

Combine like terms: 12 + 6 = 18
22 + -2c = 18 + 2c

Solving
22 + -2c = 18 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
22 + -2c + -2c = 18 + 2c + -2c

Combine like terms: -2c + -2c = -4c
22 + -4c = 18 + 2c + -2c

Combine like terms: 2c + -2c = 0
22 + -4c = 18 + 0
22 + -4c = 18

Add '-22' to each side of the equation.
22 + -22 + -4c = 18 + -22

Combine like terms: 22 + -22 = 0
0 + -4c = 18 + -22
-4c = 18 + -22

Combine like terms: 18 + -22 = -4
-4c = -4

Divide each side by '-4'.
c = 1

Simplifying
c = 1

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