25+2d-50=(d+2d-50)-75

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Solution for 25+2d-50=(d+2d-50)-75 equation: 



25+2d-50=(d+2d-50)-75

We move all terms to the left:

25+2d-50-((d+2d-50)-75)=0

We add all the numbers together, and all the variables

2d-((3d-50)-75)+25-50=0

We add all the numbers together, and all the variables

2d-((3d-50)-75)-25=0



We calculate terms in parentheses: -((3d-50)-75), so:

(3d-50)-75

We get rid of parentheses

3d-50-75

We add all the numbers together, and all the variables

3d-125

Back to the equation:

-(3d-125)



We get rid of parentheses

2d-3d+125-25=0

We add all the numbers together, and all the variables

-1d+100=0

We move all terms containing d to the left, all other terms to the right

-d=-100

d=-100/-1

d=+100

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