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25(x*x)+20x=10
We move all terms to the left:
25(x*x)+20x-(10)=0
We add all the numbers together, and all the variables
25(+x*x)+20x-10=0
We add all the numbers together, and all the variables
20x+25(+x*x)-10=0
We multiply parentheses
25x^2+20x-10=0
a = 25; b = 20; c = -10;
Δ = b2-4ac
Δ = 202-4·25·(-10)
Δ = 1400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1400}=\sqrt{100*14}=\sqrt{100}*\sqrt{14}=10\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-10\sqrt{14}}{2*25}=\frac{-20-10\sqrt{14}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+10\sqrt{14}}{2*25}=\frac{-20+10\sqrt{14}}{50} $
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