25(3y/5+3/2)=7y/10

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Solution for 25(3y/5+3/2)=7y/10 equation: 


y in (-oo:+oo)

25*((3*y)/5+3/2) = (7*y)/10 // - (7*y)/10

25*((3*y)/5+3/2)-((7*y)/10) = 0

25*((3*y)/5+3/2)+(-7/10)*y = 0

25*(3/5*y+3/2)+(-7*y)/10 = 0

(10*25*(3/5*y+3/2))/10+(-7*y)/10 = 0

10*25*(3/5*y+3/2)-7*y = 0

143*y+375 = 0

(143*y+375)/10 = 0

(143*y+375)/10 = 0 // * 10

143*y+375 = 0

143*y+375 = 0 // - 375

143*y = -375 // : 143

y = -375/143

y = -375/143

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