25(2x-3)=125(x+1)

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Solution for 25(2x-3)=125(x+1) equation: 



25(2x-3)=125(x+1)

We move all terms to the left:

25(2x-3)-(125(x+1))=0

We multiply parentheses

50x-(125(x+1))-75=0



We calculate terms in parentheses: -(125(x+1)), so:

125(x+1)

We multiply parentheses

125x+125

Back to the equation:

-(125x+125)



We get rid of parentheses

50x-125x-125-75=0

We add all the numbers together, and all the variables

-75x-200=0

We move all terms containing x to the left, all other terms to the right

-75x=200

x=200/-75

x=-2+2/3

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